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The Charge On A Parallel Plate Capacitor Is Varying As Q Q0sin 2pnt The Plates Are Very Large And Close Together Neglecting The Edge Effects The Displacement Current Through The

If Q Is The Charge On The Capacitor And E Is The Magnitude Of The Electric Field Between The Plates The Force On Each Plate Of The Capacitor Is

Three Charges Q1 Q2 And Q Are Placed On A Straight Line Such That Q Some Where In Between Q1 And Q2 If This System Of Charges

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Three Identical Metal Plates With Large Surface Areas Are Kept Parallel To Each Other As Shown In Figure The Leftmost Plate Is Given A Charge Q The Rightmost A Charge 2q

Q A Parallel Plate Capacitor Of Area A Plate Separation D And Capacitance C Is Filled

Derive The Expression For The Capacitance Of A Parallel Plate Capacitor

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Four Identical Parallel Conductors Carrying Charges Q 2q 3q And 4q Are Placed As Shown In The Figure The Plates Carrying Charges Q And 4q Are Connected Through A Switch

In The Figure Shown The Effective Capacity Across P And Q Is Area Of Each Plate Is A

Https Encrypted Tbn0 Gstatic Com Images Q Tbn 3aand9gctc5lzpqy37t6fxjfjxexfey93neiorjna14qpanogc 6wtcva4 Usqp Cau

Three Identical Parallel Conducting Plates A B And C Are Placed As Shown Switches S1 And S2 Are Open And Can Connect A And C To Earth When Closed Q Charge

A Charge Of 1 M C Is Given To One Plate Of A Capacitors And A Charge Of 2 M C Is Given To The Other Plate Of A 0 1 M F

One Plate Of A Capacitor Is Connected To A Spring As Shown In Figure Area Of Both The Plates Is A In Steady State Separation Between The Plates Is 0 8d Spring Was

Force Acting Upon A Charged Particle Kept Between The Plates Of Charged Capacitor Is F If One Of The Plates Of The Capacitor Is Removed Force Acting On The Same Particle

A Charge Q Is Distribute Uniformly On A Ring Radius R A Sphere Of Equal Radius R Is Constructed With Its Center At The Periphery Of The Ring Find The Flux Of